The one idea the whole topic rests on
Horizontal and vertical motion are independent. Gravity pulls downwards and does nothing at all sideways, so in the absence of air resistance the horizontal velocity never changes while the vertical velocity falls steadily at g metres per second every second. A projectile is therefore two simple problems happening at once, not one complicated one.
That single idea generates every formula in the topic. With launch speed v at angle theta, and no air:
- Horizontal: distance equals v cos theta multiplied by time. Constant speed, nothing else to say.
- Vertical: height equals launch height plus v sin theta multiplied by time, minus one half g time squared. Standard constant-acceleration motion.
- Flight time on level ground: 2 v sin theta divided by g, which is simply the time to slow to a stop vertically, doubled.
- Maximum height: v sin theta all squared, divided by 2g.
- Range on level ground: v squared times sin of 2 theta, divided by g.
Two consequences catch people out. First, a ball thrown horizontally and a ball dropped from the same height hit the ground at exactly the same moment, because their vertical stories are identical. Second, the range formula depends on sin of twice the angle, and sine is symmetric about 90 degrees, so 30 degrees and 60 degrees give the same range. Complementary angles always do.